Simple Geometric Proofs
Authored by Anthony Clark
Mathematics
10th Grade
CCSS covered
Used 7+ times
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12 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
Step 6: m∠2 = 15⁰
Step 7: m∠1 = m∠2
Step 8: ∠1 ≅ ∠2
Step 9: AM bisects ∠LAN
What is the justification for Step 9?
Symmetric property of congruence
Definition of angle bisector
Addition property of equality
Definition of congruent angles
Tags
CCSS.HSG.SRT.B.5
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
Reason 2: Segment addition postulate
What is Step 2?
AC = AB + AB
AB = BC
AB + BC = AC
AB + AB = AB + BC
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
Reason 2: Segment addition postulate
Reason 3: Transitive property of equality
What is Step 3?
AC = AB + AB
AB = BC
AB + BC = AC
AB + AB = AB + BC
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Given: ∠1 is a complement of ∠2 and ∠2 ≅ ∠3
Prove: ∠1 is a complement of ∠3
Reason 1: Given
Reason 2: Given
What is Step 2?
∠2 ≅ ∠3
m∠1 + m∠2 = 90⁰
m∠2 = m∠3
m∠1 + m∠3 = 90⁰
Tags
CCSS.7.G.B.5
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Given: ∠1 is a complement of ∠2 and ∠2 ≅ ∠3
Prove: ∠1 is a complement of ∠3
Reason 1: Given
Reason 2: Given
Reason 3: Definition of complementary angles
Reason 4: Definition of congruent angles
What is Step 4?
∠2 ≅ ∠3
m∠1 + m∠2 = 90⁰
m∠2 = m∠3
m∠1 + m∠3 = 90⁰
Tags
CCSS.7.G.B.5
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Given: ∠1 is a complement of ∠2 and ∠2 ≅ ∠3
Prove: ∠1 is a complement of ∠3
Reason 1: Given
Reason 2: Given
Reason 3: Definition of complementary angles
Reason 4: Definition of congruent angles
Reason 5: Substitution property of equality
Reason 6: Definition of complement
What is Step 6?
∠1 is a complement of ∠3
m∠1 + m∠2 = 90⁰
m∠2 = m∠3
m∠1 + m∠3 = 90⁰
Tags
CCSS.7.G.B.5
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰
What is the justification for Step 1?
Given
Substitution
Angle addition postulate
Definition of congruent angles
Tags
CCSS.HSG.SRT.B.5
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