Factoring Polynomials and Quadratics

Hank factored 5n²-18n+9. His work is shown in the image. Is he correct? Why/why not?

• No, he set up the number puzzle wrong and found the wrong numbers that make the product and sum.

• No, he forgot to split the middle term using -15n and -3n to factor by grouping.

• Yes, those are the correct values to put into each factor.

• Yes, he's correct because he's a math teacher's son. ;)

• (2x + 1)(x + 15)

• (2x - 3)(x - 5)

• (x + 5)(2x + 3)

• 2(x - 3)(x - 5)

• prime

Factor completely:
16x^2+60x-100

• (4x - 5)(x + 5)

• (x - 5)(4x + 5)

• 4(x - 5)(4x + 5)

• 4(4x - 5)(x + 5)

If given the difference of two squares, such as x² - 25, what could you put for the middle term (a.k.a. "linear term"), so that you can factor it as a quadratic trinomial?

• 0x

• 5x

• -5x

• You cannot factor the difference of two squares.

Which number puzzle below shows how to set up the values correctly to factor a quadratic trinomial?

• 
• 
• 
• 

What is the first step when factoring polynomials?

• Find the GCF

• List all the terms

• Make the X and fill in the top and bottom

• Multiply a and c

Factor using GCF or monomial factoring: 2n²-8n³

• 2n²(n-4n²)

• 2n²(1-4n)

• 2n³(10-8n²)

• 3n(1-4n)

Factor completely: x²+16x+64

• (x+4)(x+16)

• (x-8)(x-8)

• (x+2)(x+32)

• (x+8)(x+8)

What are the x-intercepts (zeros)?

• (-2,0) and (2,0)

• (0,2) and (0,-2)

• (0,-4)

• (-2,-4) and (2,-4)

What are the x-intercepts? (check all that apply)

• none

• (8,-1)

• (1,0)

• (-3,0)