Solving Polynomials Equations by Factoring

Solve the equation using the zero product property.

3x(2x - 4) = 0

• x = -1/3 or x = -2

• x = 0 or x = 2

• x = 0 or x = -2

• x = -1/3 or x = 2

Tags

CCSS.HSA-REI.B.4B

What are the factors of
25x² - 81?

• (5x - 9)(5x + 9)

• (5x - 9)(5x - 9)

• (5x + 9)(5x + 9)

• Cannot be factored

Tags

CCSS.HSA.APR.C.4

Factor Completely:  3n² - 15n + 18

• (n - 2)(n - 3)

• 3(n + 2)(n + 3)

• (3n - 9)(n - 2)

• 3(n - 3)(n - 2)

• ± 1
• ± 4/3
• ± 3/4
• No real solution

Tags

CCSS.8.EE.A.2

Which of the following is a difference of perfect squares?

• x² - 18

• 4x² + 36 

• 9x² - 100

• x² + 4

Tags

CCSS.HSA.APR.C.4

What are the solutions?

• 0 and 8

• -2 and -4

• 3 and -1

• 2 and 4

Solve by factoring:  2x²+ 7x + 6 = 0

• x= 3/2 and x = 2

• x = -3/2 and x = -2

• x = 6 and x = 7

• x = -6 and x = -7

Tags

CCSS.HSA-REI.B.4B

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x

• Solve for x

• FOIL

• Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B

Solve by factoring:
x² - 9x = 0

• 9

• 0, 9

• -9, 0

• -9

Tags

CCSS.HSA-REI.B.4B

What property would you use to solve the following?
(x-3)(x+2)=0

• Commutative Property

• Associative Property

• Zero Product Property

• Inverse Property

Tags

CCSS.HSA-REI.B.4B