Factoring Polynomials with the Middle Term Split

Factor the following expression: 𝑥² − 3𝑥 – 18

• (𝑥 + 6) (𝑥 − 3)

• (𝑥 − 6) (𝑥 + 3)

• (𝑥 − 6) (𝑥 − 3)

• (𝑥 + 6) (𝑥 − 4)

Hank factored 5n²-18n+9. His work is shown in the image. Is he correct? Why/why not?

• No, he set up the number puzzle wrong and found the wrong numbers that make the product and sum.

• No, he forgot to split the middle term using -15n and -3n to factor by grouping.

• Yes, those are the correct values to put into each factor.

• Yes, he's correct because he's a math teacher's son. ;)

• two quadratic trinomials

• four monomials

• two linear binomials

• (x + 4)(x - 10)

• (x - 2)(x - 20)

• (x - 5)(x - 8)

• (x - 4)(x - 10)

Factor

• 16y⁴(2+y)(2-y)

• 16y⁴(2+y²)

• (2+y)(2-y)

• 4y⁴(2x+y)(2x-y)

Tags

CCSS.HSA.APR.C.4

• x + 7

• x + 30

• x² + 7

• x² + 30

Tags

CCSS.HSA.APR.D.6

Factor

• (x+3)(5x+2)(5x-2)

• (x+2)(3x-5)(3x+5)

• (x+3)(2x+5)(2x-5)

• (x-3)(2x+5)(2x-5)

• (2x + 1)(x + 15)

• (2x - 3)(x - 5)

• (x + 5)(2x + 3)

• 2(x - 3)(x - 5)

• prime

Factor completely:

Which number puzzle below shows how to set up the values correctly to factor a quadratic trinomial?

• 
• 
• 
•