
Solving System of Equations Substitution Method
Authored by Anthony Clark
Mathematics
9th Grade
CCSS covered

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13 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Example 1
Step 3:
After substituting the first equation into the second one and working it out, I got
x = 1.
What should I do next? Then do it.
Fill in 1 for x in y = 6x
y = 6(1)
y = 6
Fill in 1 for y in y = 6x
1 = 6x
1/6 = x
Fill in 1 for y in 2x + 5y = 32
2x + 5(1) = 32
2x + 5 = 32
2x = 27
x = 27/2
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Example 1
Step 4:
What is the solution to the system:
y = 6x
2x + 5y = 32
Given I got x = 1 from step 2 and y = 6 from step 3.
(1, 6)
(6, 1)
Tags
CCSS.HSA.REI.C.7
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which statement would be correct for step 1 and do it?
I would solve the first equations for y because it has a coefficient of 1.
y = -x
I would solve the first equations for y because it has a coefficient of -1.
-y = -x
I would solve the first equations for x because it has a coefficient of 1.
x = y
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
In step 1, we got x = y. Which shows the correct steps for step 2 (substituting and solving)?
18x + 2y = 0
18(y) + 2y = 0
20y = 0
No Solution
18x + 2y = 0
18(y) + 2y = 0
20y = 0
y = 0
Tags
CCSS.8.EE.C.8B
5.
FILL IN THE BLANK QUESTION
1 min • 1 pt
x - y = 0
18x + 2y = 0
Step 4:
In step 2, we got x = 0 and y = 0, what is the final answer?
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which statement is correct to begin to solve this equation?
The variable is already isolated in the first equation, so we have already solved it.
The variable is already isolated in the first equation, so we have to plug into the second one like this:
-4(4-2x) - 2y = -8
The variable is already isolated in the first equation, so we have to plug into the second one like this:
-4x - 2(4 - 2x) = -8
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Example 3: y = 4 - 2x -4x - 2y = -8 Finish step 2 (which shows correct steps): -4x - 2(4 - 2x) = -8
-4x - 2(4 - 2x) = -8
-4x - 8 + 4x = -8
8 = -8
-4x - 2(4 - 2x) = -8
-4x - 8 - 4x = -8
-8x - 8 = -8
-8x = 0
x = 0
-4x - 2(4 - 2x) = -8
-4x - 8 + 4x = -8
-8 = -8
-4x - 2(4 - 2x) = -8
-4x - 8 - 2x = -8
-6x - 8 = -8
-6x = 0
x = 0
Tags
CCSS.8.EE.C.7B
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