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Solving Quadratic Equations by Completing the Square

Authored by Anthony Clark

Mathematics

9th Grade

CCSS covered

Solving Quadratic Equations by Completing the Square
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10 questions

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1.

FILL IN THE BLANK QUESTION

1 min • 1 pt

Solve the quadratic Equation by completing the square.  Round off to 1 decimal place. 

Answer explanation

 (2x+1)2=16\left(2x+1\right)^2=16  
 (2x+1)2=16\sqrt{\left(2x+1\right)^2}=\sqrt{16}  
 2x+1=±42x+1=\pm4  
 x=412=32x=\frac{4-1}{2}=\frac{3}{2} 
 x=412=52x=\frac{-4-1}{2}=\frac{-5}{2}  

Tags

CCSS.HSA-REI.B.4B

2.

FILL IN THE BLANK QUESTION

1 min • 1 pt

Answer explanation

 x=973=163x=\frac{-9-7}{-3}=\frac{16}{3}   (73x)2=81\left(7-3x\right)^2=81  
 (73x)2=81\sqrt{\left(7-3x\right)^2}=\sqrt{81}  
 73x=±97-3x=\pm9  
 x=973=163x=\frac{-9-7}{-3}=\frac{16}{3} 
 x=973=23x=\frac{9-7}{-3}=\frac{-2}{3}  

Tags

CCSS.HSA-REI.B.4B

3.

FILL IN THE BLANK QUESTION

1 min • 1 pt

Solve the quadratic Equation by completing the square round off to 2 decimal places.

Answer explanation

 x=61=3.45x=-\sqrt{6}-1=-3.45   x2+2x+(22)2(22)25=0x^2+2x+\left(\frac{2}{2}\right)^2-\left(\frac{2}{2}\right)^2-5=0  
 x2+2x+115=0x^2+2x+1-1-5=0  
 (x+1)26=0\left(x+1\right)^2-6=0 
 (x+1)2=6\sqrt{\left(x+1\right)^2}=\sqrt{6}  
 x+1=±6x+1=\pm\sqrt{6}  
 x=±61x=\pm\sqrt{6}-1  
 x=61=1.45x=\sqrt{6}-1=1.45   x=61=3.45x=-\sqrt{6}-1=-3.45  

Tags

CCSS.HSA-REI.B.4B

4.

FILL IN THE BLANK QUESTION

1 min • 1 pt

Answer explanation

 x212x+9=0x^2-12x+9=0   x212x+(122)2(122)2+9=0x^2-12x+\left(\frac{-12}{2}\right)^2-\left(\frac{-12}{2}\right)^2+9=0  
 x212x+3636+9=0x^2-12x+36-36+9=0  
 (x6)227=0\left(x-6\right)^2-27=0 
 (x6)2=27\sqrt{\left(x-6\right)^2}=\sqrt{27}  
 x6=±5.20x-6=\pm5.20  
 x=5.20+6=11.20x=5.20+6=11.20  
 x=5.20+6=0.80x=-5.20+6=0.80   

Tags

CCSS.HSA-REI.B.4B

5.

FILL IN THE BLANK QUESTION

1 min • 1 pt

Solve the quadratic Equation by completing the square.  Round off to 2 decimal places

Answer explanation

(2x+1)2=16\left(2x+1\right)^2=16
(2x+1)2=16\sqrt{\left(2x+1\right)^2}=\sqrt{16}
2x+1=±42x+1=\pm4
x=412=32x=\frac{4-1}{2}=\frac{3}{2}
x=412=52x=\frac{-4-1}{2}=\frac{-5}{2}

Tags

CCSS.HSA-REI.B.4B

6.

FILL IN THE BLANK QUESTION

1 min • 1 pt

Answer explanation

  14+x3x2=414+x-3x^2=4    3x2x14+4=03x^2-x-14+4=0  
 3x23x3103=0\frac{3x^2}{3}-\frac{x}{3}-\frac{10}{3}=0 
 x213x+(16)2(16)2103=0x^2-\frac{1}{3}x+\left(\frac{1}{6}\right)^2-\left(\frac{1}{6}\right)^2-\frac{10}{3}=0 
 (x16)2136(103×1212)\left(x-\frac{1}{6}\right)^2-\frac{1}{36}-\left(\frac{10}{3}\times\frac{12}{12}\right)  

 (x16)213612036=0\left(x-\frac{1}{6}\right)^2-\frac{1}{36}-\frac{120}{36}=0  

 (x16)212136=0\left(x-\frac{1}{6}\right)^2-\frac{121}{36}=0   (x16)2=12136\sqrt{\left(x-\frac{1}{6}\right)^2}=\sqrt{\frac{121}{36}}    x16=±116x-\frac{1}{6}=\pm\frac{11}{6}   x=±116+16x=\pm\frac{11}{6}+\frac{1}{6}   x=2,53x=2,\frac{-5}{3}  

Tags

CCSS.HSA-REI.B.4B

7.

FILL IN THE BLANK QUESTION

1 min • 1 pt

Answer explanation

 (x+1)2=9\left(x+1\right)^2=9  
 (x+1)2=9\sqrt{\left(x+1\right)^2}=\sqrt{9}  
 x+1=±3x+1=\pm3  
 x=31=2x=3-1=2 
 x=31=4x=-3-1=-4  

Tags

CCSS.HSA-REI.B.4B

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