Shaded Grids Rectangles
Quiz
•
Mathematics
•
3rd Grade
•
Practice Problem
•
Hard
+1
Standards-aligned
Anthony Clark
FREE Resource
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8 questions
Show all answers
1.
OPEN ENDED QUESTION
1 min • 1 pt
The figure below shows a big shaded rectangle with a small rectangle cut out of it.
a. Area of the shaded rectangle before it was cut: _ x _ = _
Evaluate responses using AI:
OFF
Tags
CCSS.3.MD.C.7D
2.
OPEN ENDED QUESTION
1 min • 1 pt
The figure below shows a big shaded rectangle with a small rectangle cut out of it. b. Area of the unshaded rectangle: _ x _ = _
Evaluate responses using AI:
OFF
Tags
CCSS.3.MD.C.7D
3.
OPEN ENDED QUESTION
1 min • 1 pt
The figure below shows a big shaded rectangle with a small rectangle cut out of it. c. Area of the shaded rectangle after it was cut: _ - _ = _
Evaluate responses using AI:
OFF
Tags
CCSS.3.MD.C.7D
4.
OPEN ENDED QUESTION
1 min • 1 pt
The figure below shows a small rectangle cut out of a big rectangle. Find the area of the shaded part of the figure.
Evaluate responses using AI:
OFF
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
All of these rectangles have the same area. Use the associative property and move the parenthesis to find the unknown side lengths.
8 x 6 = 48
Area = 48 sq. cm.
8 x 6 = 40
Area = 40 sq. cm.
Tags
CCSS.3.MD.C.7B
CCSS.4.MD.A.3
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Label the side lengths of each part of the rectangle. Then, find the total area of the large rectangle by adding the areas of the two smaller rectangles together.
( 4 + 4 ) x 7
(4 x 7 ) + (4 x 7 )
28 + 28
area = 56
( 5 + 5 ) x 7
(5 x 7 ) + (5 x 7 )
35 + 35
area = 70
( 5 + 4 ) x 7
(5 x 7 ) + (4 x 7 )
35 + 28
area = 63
( 7 + 7 ) x 7
(7 x 7 ) + (7 x 7 )
49 + 49
area = 98
Tags
CCSS.3.MD.C.7D
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Label the side lengths of each part of the rectangle. Then, find the total area of the large rectangle by adding the areas of the two smaller rectangles together.
3 x (10 + 3)
(3 x 10) + (3 x 3)
30 + 9
area = 39
13 x (10 + 3)
(13 x 10) + (13 x 3)
130 + 39
area = 169
10 x (10 + 3)
(10 x 10) + (10 x 3)
100 + 30
area = 130
3 x (10 + 3)
(3 x 10) + (3 x 10)
30 + 30
area = 60
Tags
CCSS.4.NBT.B.5
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