Center Angle Bisector

Center Angle Bisector

10th Grade

14 Qs

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Center Angle Bisector

Center Angle Bisector

Assessment

Quiz

Mathematics

10th Grade

Practice Problem

Medium

CCSS
HSG.C.A.3, HSG.CO.C.9, 4.MD.C.7

Standards-aligned

Created by

Anthony Clark

Used 1+ times

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14 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The INCENTER is the intersection of which special segments?

Angle Bisectors

Perpendicular Bisectors

Medians

Altitudes

Tags

CCSS.HSG.C.A.3

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The place where all three angle bisectors meet is called the ...

Circumcenter

Orthocenter

Incenter

Centroid

Tags

CCSS.HSG.C.A.3

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

The figure is an example of a(n) ...

angle bisector

perpendicular bisector

median

midsegment

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What type of center is point M?

Circumcenter

Incenter

Centroid

Orthocenter

Tags

CCSS.HSG.C.A.3

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

If S is the incenter, what type of segments are drawn?

medians

angle bisectors

perpendicular bisectors

altitudes

Tags

CCSS.HSG.C.A.3

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Angle JHG measures 161.

m∠GHK=80.5,

m∠KHJ=161

m∠GHK=161,

m∠KHJ=80.5

m∠GHK=80.5,

m∠KHJ=80.5

m∠GHK=161,

m∠KHJ=161

Tags

CCSS.HSG.CO.C.9

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰ 
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
Step 6: m∠2 = 15⁰
Step 7: m∠1 = m∠2
Step 8: ∠1 ≅ ∠2
Step 9: AM bisects ∠LAN
What is the justification for Step 9?

Symmetric property of congruence

Definition of angle bisector

Addition property of equality

Definition of congruent angles

Tags

CCSS.HSG.CO.C.9

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