Tangent Lines with Trig Equations

Using trigonometric functions, find the equation of the tangent line to the curve y = tan(2x) at the point (π/4, 2)

• y - 2 = 2cos^2(π/4)(x - π/4)

• y - 2 = 2cot^2(π/4)(x - π/4)

• y - 2 = 2sec^2(π/4)(x - π/4)

• y - 2 = 2csc^2(π/4)(x - π/4)

Applying the derivative, find the equation of the tangent line to the curve y = sin(x) at the point (π/4, √2/2)

• y = (1/√2)x + (√2/2 + 1/√2π/4)

• y = (1/√2)x + (√2/2 - 1/√2π/2)

• y = (1/√2)x + (√2/2 + 1/√2π/2)

• y = (1/√2)x + (√2/2 - 1/√2π/4)

Finding the equation of the tangent line to the curve y = 2cos(x) at the point (π/4, √2)

• y = 2x + √2 + π

• y = 2x + √2 - π

• y = -2x + √2 + 2π

• y = -2x + √2 - 2π

What is the equation of the graph shown?

• y = tanθ/2

• y = tan2θ

• y = tanθ/4

• y = tan4θ

Find the solution over the interval [0, 2π)

• 0, π, π/6, 5π/6,

• 0, π/6, 7π/6

• π, 5π/6, 11π/6

• π, π/6, 5π/6, 7π/6, 11π/6

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What is the equation of the graph shown?

• y = tan θ

• y = sin θ

• y = cos θ

• y = -5tan θ

What is the value of a if the function above is f(x) = a tan x

• 1/2

• 1

• 2

• 4

What is the equation for the graph shown.

• y = 4sinθ - 2

• y = 3tcosθ - 1

• y = 2tanθ - 4

• y = 2-4tanθ + 2

Finding the equation of the tangent line to the curve y = tan(x) at the point (π/3, √3)

• y = √3 + √3(x - π/3)

• y = √3 - √3(x + π/3)

• y = √3 - √3(x - 2π/3)

• y = √3 - √3(x - π/3)