Multiplying Binomials with Special Cases

(x² + 12)(x² - 12) =

• x² - 144

• x⁴ - 144

• x - 144

• x⁴ + 144

BOX 4: Multiply the binomials.

(x + 8)(x - 8)

• x² + 8x + 64

• x² + 64

• x² - 64

• x² + 16x - 64

(y + 2)(y - 2)

• y² + 4

• y² + 4y - 4

• y² - 4y + 4

• y² - 4

(c + 9)(c - 9)

• c² - 81

• c² + 81

• c² - 18c - 81

• c² + 18c - 81

Multiply:

(7x - 2y)²

• 49x² - 4y²

• 49x² - 28xy + 4y²

• 14x² - 28xy + 14y²

• 49x² + 28xy + 4y²

Multiply:

(a - b)²

• a² - b²

• a² - 2ab - b²

• a² + 2ab + b²

• a² - 2ab + b²

Multiply the binomials.

(x + 8)(x - 8)

• x² + 8x + 64

• x² + 64

• x² - 64

• x² + 16x - 64

Find the product:
(n - 5)(n - 1)

• n² - 5n + 5

• n² - 6n + 5

• n² + 5

• n² + 6n + 5

Which of the following is the correct set up for the Box Method when multiply (x + 3) (2x - 4) _{(click on the question to see the image in the background)}

• A

• B

• C

• D