Factoring Quadratics

Solve:

3x² + 18x +15 = 0

Hint: Factor GCF first.

• x = 3, 2

• x = 5, 1

• x = -5, -1

• x = -3, -2

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 2x - 24 = 0

• x = -6, x = 4

• x = 6, x = -4

• x = 12, x = -2

• x = 8, x = -3

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 9x + 20 = 0

• x = -2, x = -10

• x = -3, x = -4

• x = -4, x = -5

• x = -4, x = -6

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 7x + 12 = 0

• x = -2, x = -10

• x = -3, x = -4

• x = -4, x = -5

• x = -4, x = -6

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 13x + 12 = 0

• x = -1, x = -12

• x = -1, x = -24

• x = -2, x = -6

• x = -2, x = -12

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:

(2x - 1)(x + 4) = 0

• x = 1/2 or -4

• x = 1/2 or 4

• x = 2 or -4

• x = -2 or 4

Tags

CCSS.HSA-REI.B.4B

In the equation
 (x + 2)(x - 3) = 0, the binomials are called...?

• Factors

• Products

• Multiples

• Zeros

Tags

CCSS.HSA.APR.B.2

• 2 and 3

• -2 and -3

• 2 and -3

• -2 and 3

Tags

CCSS.HSA-REI.B.4B

• Yes, she factored correctly and then used the zero product property

• No, she didn't factor correctly so the rest of her work is wrong.

• No, she did not set the equation equal to zero before factoring.

Tags

CCSS.HSA-REI.B.4B

Solve

• b=4/5, b=3

• b=4, b=-3

• b=1/5, b=3

• b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B