An object in launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. Its height is represented by the equation s(t) = –16t2 + 64t + 80. What will be the object's maximum height?
Quadratic Equation Applications Trivia

Quiz
•
Mathematics
•
9th Grade
•
Hard
Anthony Clark
FREE Resource
16 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
2 ft
80 ft
144 ft
64 ft
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A diver is standing on a platform above the pool. He jumps form the platform with an initi8al upward velocity of 8 ft/s. Use the formula h t = −16 t2 + 8t + 24, where h is his height above the water, t is the time, v is his starting upward velocity, and s is his starting height. How high is the platform?
.25 ft
24 ft
25 ft
8 ft
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The function f(t) = -5t2+20t + 60 models the approximate height of an object t seconds after it is launched. How many seconds does it take the object to hit the ground?
4 seconds
-2 seconds
6 seconds
9 seconds
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the vertex of y=x2+4x+3?
(2,1)
(-2,1)
(0,0)
(-2,-1)
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the vertex of the parabola: y=2(x-3)2+4.
Explain how you got your answer.
(3,4)
(-3,4)
(3, -4)
(-3,-4)
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The profit from selling local ballet tickets depends on the ticket price. Using past receipts, we find that the profit can be modeled by the function p= -15x2 +600x +60 , where x is the price of each ticket. What is the maximum profit you can make from selling tickets?
$6060
$20
$600
$10,250
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Jason launched a rocket for a physics experiment. This equation can be used to find the height (h), in feet, of the rocket after t seconds.
h = -16t2 + 288t + 8
How many seconds will it take for the rocket to reach a height of 1,304 feet?
9.0 seconds
9.6 seconds
81.0 seconds
82.0 seconds
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