Standard to Vertex Form Quadratic

If we have the equation y=ax²+bx+c, how can we can find the x-coordinate (the "h" value) of the vertex?

• -a

• -b/a

• b/2a

• -b/2a

If given the equation y = 3(x + 5)² - 4, what is the vertex of the parabola?

• (5, -4)

• (-5, -4)

• (-15, -4)

• (15, -4)

Fill in the blank: When we convert from standard to vertex form, the "a" value will ____________.

• stay the same

• be the same but negative

• become the vertex

• be squared

Which equation has a vertex of (-3, 4)? Hint: (the vertex is (h,k))

• y = 2(x+3)² + 4

• y = (x+3)² - 4

• y = (x-3)² + 4

• y = 2(x - 3)² + 4

Which value in the vertex form a(x - h)²+ k represents the y-value of the vertex?

• a

• h

• k

Which of the following equations matches standard form of a quadratic?

• ax + by = c

• y = a(x - h)² + k

• y = ax² + bx + c

• y = mx + b

Write the following quadratic expression in completed square form... x² + 10x + 23

• (x + 5)² - 2

• (x + 5)² + 2

• (x + 5)² + 13

• (x + 5)² - 13

Write the following quadratic expression in completed square form... x² - 10x - 4

• (x - 5)² - 29

• (x - 5)² - 21

• (x + 5)² + 14

• (x + 5)² - 29

Write the following quadratic expression in completed square form... x² - 10x + 18

• (x - 5)² + 7

• (x - 5)² - 7

• (x + 5)² + 7

• (x + 5)² - 7

Write the following quadratic expression in completed square form...

x² - 6x + 4

• (x - 3)² - 5

• (x - 3)² - 13

• (x - 3)² + 5

• (x - 3)² + 4