Drawing Slope from Slope Intercept Form

Find the slope:

• 3/4

• 4/3

• -3/4

• -4/3

Tags

CCSS.8.EE.B.5

Write the slope-intercept form of the equation of each line.

Identify the slope and y intercept in the equation of the line: y = -1/3x + 1

• Slope: 1/3
  y-intercept: 1

• Slope: 1/3
  y-intercept: -1

• Slope: -1/3
  y-intercept: 1

• Slope: -1/3
  y-intercept: 0

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Which line is perpendicular to this line:
y=1/3x+7

• y=-3x+8

• y=1/3x+2

• y= 3x+1

• y=-1/3x

Graph the equation y = 2x + 3.

• 
• 
• 
• 

Graph the equation y = -3x + 1.

• Graph the equation y = -3x + 1 by plotting the points (0, 1) and (1, -2) and drawing a straight line passing through them.

• Graph the equation y = -3x + 1 by plotting the points (0, 1) and (1, 0) and drawing a straight line passing through them.

• Graph the equation y = -3x + 1 by plotting the points (0, 1) and (1, -1) and drawing a straight line passing through them.

• Graph the equation y = -3x + 1 by plotting the points (0, 1) and (1, 2) and drawing a straight line passing through them.

Graph the equation y = 1/2x - 2.

• 
• 
• 
• 

Graph the equation y = -4x + 5.

• Graph the equation y = -4x + 5 as a parabola.

• Graph the equation y = -4x + 5 as a straight line passing through the points (0, 5) and (1, 1).

• Graph the equation y = -4x + 5 as a horizontal line.

• Graph the equation y = -4x + 5 as a vertical line.

Graph the equation y = 3x - 4.

• Graph is a straight line

• Graph is a parabola

• Graph is a circle

• Graph is a curve

Graph the equation y = -2x + 2.

• Graph the equation y = -2x + 2 by plotting the points (0, 2) and (1, 0) and connecting them with a straight line.

• Graph the equation y = -2x + 2 by plotting the points (0, 2) and (1, 4) and connecting them with a straight line.

• Graph the equation y = -2x + 2 by plotting the points (0, 2) and (1, -2) and connecting them with a straight line.

• Graph the equation y = -2x + 2 by plotting the points (0, 0) and (1, 2) and connecting them with a straight line.