Circles in Standard Form

Determine the equation of the circle in standard form: x² + y² + 4x + 6y - 36 = 0

• (x + 2)² + (y + 3)² = 49

• (x + 2)² + (y + 3)² = 13

• (x - 2)² + (y - 3)² = 49

• (x - 2)² + (y - 3)² = 13

Tags

CCSS.HSG.GPE.A.1

In the equation (x + 2)² + (y - 3)²=4, the radius of the circle is...

• 4

• 2

• 3

• 16

Tags

CCSS.HSG.GPE.A.1

Write the standard equation of the circle with the given center and radius; center (0,0) and radius: 4

• x² + y² = 4

• x² + y² = 16

• x² + y² = 2

• x² + y² = 8

Tags

CCSS.HSG.GPE.A.1

The point (0, 0) is on a circle whose center is at (0,3). Write the standard form of the equation of the circle.

• x² + (y - 3)² = 9

• x² + (y - 3)² = 3

• (x + 1)² + (y - 3)² = 3

• (x + 1)² + (y - 3)² = 9

Tags

CCSS.HSG.GPE.A.1

The point (4,5) is on a circle whose center is at (-2,1). Write the standard form of the equation of the circle

• (x + 2)² + (y - 1)² = 20

• (x + 2)² + (y - 1)² = 52

• (x + 2)² + (y - 1)² = 12

• (x + 2)² + (y - 1)² = 10

Tags

CCSS.HSG.GPE.A.1

Determine the equation of the circle in standard form: x² + y² + 6x - 12y + 20 = 0

• (x - 3)² + (y + 6)² = 25

• (x + 3)² + (y - 6)² = 25

• (x - 3)² + (y + 6)² = 45

• (x + 3)² + (y - 6)² = 5

Tags

CCSS.HSG.GPE.A.1

Determine the center and radius:

x² + y² - 10x + 8y - 8 = 0

• C = (5,-4) r = 7

• C = (-5,4) r = 7

• C = (-4,5) r = 49

• C = (5,-4) r = 49

Tags

CCSS.HSG.GPE.A.1

Change the following equation to standard form

x² + y² - 4x - 5=0

• (x - 2)² + y² = 3

• (x - 2)² + y² = 9

• (x - 4)² + y²= 1

• (x - 4)² + (y - 1)²= 22

Tags

CCSS.HSG.GPE.A.1

Identify the center and radius: (x - 2)² + (y + 5)² = 16

• ctr: (2, -5) radius: 4

• ctr: (-2, 5) radius: 4

• ctr: (2, -5) radius: 256

• ctr: (-2, 5) radius: 256

Tags

CCSS.HSG.GPE.A.1

A circle has the equation x² + y² - 12x + 8y + 3 = 0. Write the equation in standard form.

• (x - 6)² + (y + 4)² = 49

• (x + 4)² + (y - 6)² = 49

• (x - 6)² + (y + 4)² = 55

• x² + y² = 55

Tags

CCSS.HSG.GPE.A.1