Circle Equation

The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.

• (x - 2)² + (y + 5)² = 36

• (x - 5)² + (y + 2)² = 6

• (x + 5)² + (y - 2)² = 36

• (x + 2)² + (y - 5)² = 6

Write the standard equation of the circle with the given center and radius; center (0,0) and radius: 3

• x²+y²=4

• x²+y²=81

• x²+y²=9

In the equation (x+2)²+(y-3)²=4, the center of the circle is at...

• (-2, 3)

• (-3, 2)

• (2, -3)

• (3, -2)

Find the center and radius of the circle: x² + y² + 14x - 2y = -1.

• center = (-7, 2) radius = 3

• center = (-7, 1) radius = 7

• center = (-4, 1) radius = 7

• center = (-4, 2) radius = 3

Determine the equation of the circle in standard form:

x² + y² + 4x + 6y - 36 = 0

• (x + 2)² + (y + 3)² = 49

• (x + 2)² + (y + 3)² = 13

• (x - 2)² + (y - 3)² = 49

• (x - 2)² + (y - 3)² = 13

Write the equation of a circle in standard form given the endpoints of the diameter to be (4, -3) and (10, 5)

Find the center of the circle if the endpoints of a diameter of the circle are at (-12, -7) and (3, 5).

• (-9/2, -1)

• (-15/2, -6)

• (9/2, 1)

• (15/2, 6)

What are the coordinates of the center and the radius of the circle with equation:
(x - 4)² + (y - 3)² = 25 ?

• Center (4,3)
  Radius = 5 units

• Center (4,3)
  Radius = 25 units

• Center (-4,-3)
  Radius = 25 units

• Center (-4,-3)
  Radius = 5 units

What is the center of the circle with equation x² + y² = 1?

• (1, 1)

• (0, 0)

• not enough information

What is the equation of the circle, with centre (-4,5) and radius 6 units?

• (x - 4)^2 + (y + 5)^2 = 6

• (x - 4)^2 + (y + 5)^2 = 36

• (x + 4)^2 + (y - 5)^2 = 6

• (x + 4)^2 + (y - 5)^2 = 36