Equation of Circles Center

The equation of a circle is x² + y² + 6x - 12y + 20 = 0. Write the equation in standard form.

• (x - 3)² + (y + 6)² = 25

• (x + 3)² + (y - 6)² = 25

• (x - 3)² + (y + 6)² = 45

• (x + 3)² + (y - 6)² = 5

Tags

CCSS.HSG.GPE.A.1

A circle has the equation x² + y² + 10x - 4y + 20 = 0. Write it in standard form.

• (x - 5)² + (y + 2)² = 9

• (x + 5)² + (y - 2)² = 3

• (x + 5)² + (y - 2)² = 9

• (x - 5)² + (y + 2)² = 3

Tags

CCSS.HSG.GPE.A.1

Find the center and radius of the circle: x² + y² + 14x - 2y = -1.

• center = (-7, 2) radius = 3

• center = (-7, 1) radius = 7

• center = (-4, 1) radius = 7

• center = (-4, 2) radius = 3

Tags

CCSS.HSG.GPE.A.1

Convert the equation of the circle from general to standard form.

• A

• B

• C

• D

Tags

CCSS.HSG.GPE.A.1

Select the matching graph.

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Tags

CCSS.HSG.GPE.A.1

Determine the equation of the circle in standard form:
x² + y² + 4x + 6y - 36 = 0

• (x+2)² + (y+3)² = 49

• (x+2)² + (y+3)² = 13

• (x-2)² + (y-3)² = 49

• (x-2)² + (y-3)² = 13

Tags

CCSS.HSG.GPE.A.1

Determine the equation of a circle with center (5,-3) and radius of 9

• x²+y²-10x+6y-47=4

• x²+y²-10x-6y-47=0

• 2x²+y²+10x+6y-47=0

• x²+y²-10x+6y-47=0

Tags

CCSS.HSG.GPE.A.1

In the equation (x+2)²+(y-3)²=4, the radius of the circle is...

• 4

• 2

• 3

• 16

Tags

CCSS.HSG.GPE.A.1

In the equation (x-4)²+(x-3)²=25, the center of the circle is at...

• (-3, -4)

• (4, 3)

• (-4, -3)

• (3, 4)

Tags

CCSS.HSG.GPE.A.1

Which graph corresponds to 
(x)²+ (y-6)²=9

• A

• B

• C

• D

Tags

CCSS.HSG.GPE.A.1