
Finding the Value of an Algebraic Expression
Authored by Anthony Clark
Mathematics
8th Grade
CCSS covered
Used 1+ times

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13 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Evaluate the expression. Let g = 3 h = 9
4h + 2g + 4
42
46
34
58
Tags
CCSS.6.EE.A.2C
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
If x = 2 and y = 1, then the value of 5y² + 7xy + 2x² is equal to ______.
27
144
36
14
Answer explanation
Here x = 2 and y = 1 5y² + 7xy + 2x² = 5(1)² + 7(1)(2) + 2(2)² = 5 + 14 + 2(4) = 5 + 14 + 8 = 27
Tags
CCSS.6.EE.A.2C
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
If P = 5x² + 2xy, Q = 3x² - xy + 10 and R = -4xy + 3, then what is the value of P + Q - R at x = 1 and y = -2?
5
11
31
8x² + 5xy + 7
Answer explanation
Let us first obtain the expression for P + Q - R P + Q - R = (5x² + 2xy) + (3x² - xy + 10) - (-4xy + 3) = 5x² + 2xy + 3x² - xy + 10 + 4xy - 3 = 5x² + 3x² + 2xy - xy + 4xy + 10 - 3 = 8x² + 6xy - xy + 7 = 8x² + 5xy + 7 Let's substitute the value of x = 1 and y = -2 in the expression. 8x² + 5xy + 7 = 8(1)² + 5(1)(-2) + 7 = 8 - 10 + 7 = 15 - 10 = 5
Tags
CCSS.6.EE.A.2C
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
If a = 1, then the value of a² - 3a + 5 is equal to _____.
-3
3
4
9
Answer explanation
Here a = 1 Let's put the value of a in expression a² -3a + 5 a² -3a + 5 = (1)² -3(1) + 5 = 1 - 3 + 5 = 6 - 3 = 3
Tags
CCSS.6.EE.A.2C
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Rhea has x chocolates. Shivani has 10 chocolates more than thrice the chocolates Rhea has. If x = 5, then find the total number of chocolates with Rhea and Shivani.
45
55
30
19
Answer explanation
Rhea has x chocolates Shivani has 10 more chocolates than 3 times of Rhea i.e. 3x + 10 To find the total number of chocolates, let's find the sum of x and 3x + 10 x + 3x + 10 = 4x + 10 Here x = 5 Therefore, 4x + 10 = 4(5) + 10 = 20 + 10 = 30 Therefore, there are total 30 chocolates
Tags
CCSS.6.EE.B.6
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
If p = 1, q = 2 and r = -1, then the value of p³q³ + q³r³ - r³p³ is equal to _____.
16
17
1
-1
Answer explanation
Here p = 1, q = 2 and r = -1, therefore, p³q³ + q³r³ - r³p³ = (1)³(2)³ + (2)³(-1)³ - (-1)³(1)³ = (1)(8) + (8)(-1) - (-1)(1) = 8 - 8 + 1 = 1
Tags
CCSS.6.EE.A.2C
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
If x = -1 and y = 3, what will be the result if we subtract 2x² - 3 from 4x² + 2xy + 15?
26
-14
32
14
Answer explanation
Given: x = -1 and y = 3 To find: (4x² + 2xy + 15) - (2x² - 3) (4x² + 2xy + 15) - (2x² - 3) = 4x² + 2xy + 15 - 2x² + 3 = 2x² + 2xy + 18 = 2 (-1)² + 2(-1)(3) + 18 = 2(1) - 6 + 18 = 2 - 6 + 18 = 20 - 6 = 14
Tags
CCSS.6.EE.A.2C
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