Sol 5.19 Expressions

Jordan scored two times as many points as his brother, Bradford. If Bradford scored b points, which of the following can be used to find the number of points Jordan scored?

• b x 2 (or 2b)

• b – 2

• b + 2

• b ÷ 2

Jordan scored two points less than his brother Bradford. If Bradford scored b points, which of the following can be used to find the number of points Jordan scored?

• b x 2 (or 2b)

• b – 2

• b + 2

• b ÷ 2

Jordan scored two more points than his brother, Bradford. If Bradford scored b points, which of the following can be used to find the number of points Jordan scored?

• b x 2 (or 2b)

• b – 2

• b + 2

• b ÷ 2

Jordan scored half as many points as his brother, Bradford. If Bradford scored b points, which of the following can be used to find the number of points Jordan scored?

• b x 2 (or 2b)

• b – 2

• b + 2

• b ÷ 2

Write the expression.
Four times as many apples. 

• 4 + a 

• 4a 

• 4 - a 

• a - 4

Write an algebraic expression for "12 more than number". 

• x + 12

• 12x

• x - 12

Grady has some Pokémon cards. His friend, Nick has three times the number of cards that Grady has. If g is the number of cards Grady has, which of the following could be used to find the number of cards Nick has?

• g x 3 (or 3g)

• g – 3

• g + 3

• g ÷ 3

Grady has some Pokémon cards. His friend, Nick has 3 fewer cards than Grady. If g is the number of cards Grady has, which of the following could be used to find the number of cards Nick has?

• g x 3 (or 3g)

• g – 3

• g + 3

• g ÷ 3

Grady has some Pokémon cards. His friend, Nick has 3 more cards than Grady. If g is the number of cards Grady has, which of the following could be used to find the number of cards Nick has?

• g x 3 (or 3g)

• g – 3

• g + 3

• g ÷ 3

Grady has some Pokémon cards. He decides that he is going to give them away and give an equal number to his 3 best friends. If g is the number of cards Grady has, which of the following could be used to find the number of cards Grady will give to each of his 3 friends?

• g x 3 (or 3g)

• g – 3

• g + 3

• g ÷ 3