Distance Formula, Equation of Circle, Midpoint

In the equation (x-4)²+(x-3)²=25, the radius is

• 4

• 3

• 5

• 25

• (x+1)² + (y +1)² = 3
• (x+1)² + (y -1)² = 3
• (x+1)² + (y +1)² = 9
• (x-1)² + (y -1)² = 9

What is the radius of the circle
(x+7)²+(y-2)²=144?

• 7

• 12

• 13

Find the distance between (3, 24) and (7, 56).

• 32.1

• 32.2

• 32.3

• 32.4

Determine whether the  point (5,-3) is on, inside, or outside the circle defined by x²+y²=34

• On

• Inside

• Outside

• Off the graph!

Determine whether the  point (5,-5) is on, inside, or outside the circle defined by x²+y²=34

• On

• Inside

• Outside

• Off the graph!

The endpoints of a diameter of a circle are (3,1) and (9,5).Find the equation of the circle?
Hint: In this problem, we are not given the center or radius however we can find the length of the diameter using the distance formula (Phythagoras) and then divide it by 2. The center is simply the midpoint of the given points.

• (x−6)²+(y−3)²=13

• (x−3)²+(y−6)²=13²

• (x−5)²+(y−9)²=13

• (x−9)²+(y−5)²=169/4

Which graph corresponds to 
(x-8)²+ (y+2)²=

• A

• B

• C

• D

Which graph corresponds to 
(x)²+ (y-6)²=9

• A

• B

• C

• D

Which graph corresponds to 
(x+2)²+ (y-3)²=36

• A

• B

• C

• D