Distance Formula, Equation of Circle, Midpoint
Authored by Anthony Clark
Mathematics
11th Grade
CCSS covered
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16 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
In the equation (x-4)2+(x-3)2=25, the radius is
4
3
5
25
Tags
CCSS.HSG.GPE.A.1
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Tags
CCSS.HSG.GPE.A.1
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the radius of the circle
(x+7)²+(y-2)²=144?
7
12
13
Tags
CCSS.HSG.GPE.A.1
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Find the distance between (3, 24) and (7, 56).
32.1
32.2
32.3
32.4
Tags
CCSS.HSG.GPE.B.7
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Determine whether the point (5,-3) is on, inside, or outside the circle defined by x2+y2=34
On
Inside
Outside
Off the graph!
Tags
CCSS.HSG.GPE.A.1
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Determine whether the point (5,-5) is on, inside, or outside the circle defined by x2+y2=34
On
Inside
Outside
Off the graph!
Tags
CCSS.HSG.GPE.A.1
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The endpoints of a diameter of a circle are (3,1) and (9,5).Find the equation of the circle?
Hint: In this problem, we are not given the center or radius however we can find the length of the diameter using the distance formula (Phythagoras) and then divide it by 2. The center is simply the midpoint of the given points.
(x−6)2+(y−3)2=13
(x−3)2+(y−6)2=132
(x−5)2+(y−9)2=13
(x−9)2+(y−5)2=169/4
Tags
CCSS.HSG.GPE.A.1
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