Conditional Probability and Multiplication Rule

Conditional Probability and Multiplication Rule

12th Grade

13 Qs

quiz-placeholder

Similar activities

Probability of Dependent Events

Probability of Dependent Events

12th Grade

13 Qs

Conditional Probability Word Problems

Conditional Probability Word Problems

11th Grade - University

14 Qs

IGCSE Probability

IGCSE Probability

9th - 12th Grade

10 Qs

5.3 Multiplication Rule and Conditional Probability

5.3 Multiplication Rule and Conditional Probability

12th Grade

10 Qs

Compound Probability

Compound Probability

7th Grade - University

12 Qs

5.3 Probability AP STATS

5.3 Probability AP STATS

12th Grade

18 Qs

Probability

Probability

9th - 12th Grade

10 Qs

SAT Probability Prep

SAT Probability Prep

11th Grade - University

17 Qs

Conditional Probability and Multiplication Rule

Conditional Probability and Multiplication Rule

Assessment

Quiz

Mathematics

12th Grade

Hard

Created by

Anthony Clark

FREE Resource

13 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A box contains 6 white balls and 4 black balls. What is the probability of drawing a white ball followed by a black ball without replacement?

2/5

4/15

5/15

3/10

Answer explanation

The probability of drawing a white ball first is 6/10. After removing one white ball, the probability of drawing a black ball is 4/9. Multiplying these probabilities gives 4/15.

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

If the probability of event A is 0.3 and the probability of event B given A has occurred is 0.6, what is the conditional probability of event A given B?

0.5

0.4

0.3

0.7

Answer explanation

The conditional probability of event A given B is calculated using Bayes' theorem:

P(A|B) =[ P(B|A) * P(A)] / P(B)

Substituting the given values, we get P(A|B) =( 0.6 * 0.3) / P(B)

Since P(B) = P(B|A) * P(A) + P(B|A') * P(A') =(0.6 * 0.3) + (0.6 * 0.7) = 0.6,

then P(A|B)=(0.6 * 0.3) / 0.6 = 0.3.

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A box contains 3 yellow balls, 2 green balls, and 1 red ball. Two balls are taken without replacement. What is the probability of drawing a yellow ball given that the first ball is a green ball?

1/5

1/6

2/5

1/3

Answer explanation

P(Yellow|Green)=P(Green n Yellow)/P(Green)

P(Green n Yellow)=2/6*3/5=1/5

P(Green)=2/6=1/3

Then P(Yellow|Green)=(1/5)/(1/3)=3/5

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What is the probability that they speak French given they are a girl? 

2.14

.24

.4

.8571

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What is the probability that a female is chose given they like a Toyota? 

.525

.4627

.6774

.3143

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What is P(not sport | Foreign language)?

23/37

14/23

14/37

3/23

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What is the probability that the person picked will be a boy given they speak german? 

.7273

.4

.16

.22

Create a free account and access millions of resources

Create resources
Host any resource
Get auto-graded reports
or continue with
Microsoft
Apple
Others
By signing up, you agree to our Terms of Service & Privacy Policy
Already have an account?