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Solving Systems by Graphing through Substitution and Elimination

Authored by Anthony Clark

Mathematics

9th Grade

CCSS covered

Solving Systems by Graphing through Substitution and Elimination
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14 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

To Find the solution to this system of equations, Juan decided to multiply the entire first equation by -1. What method is Juan employing to find the solution?

Substitution

Graphing

No Solution

Elimination

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What is the first step Terri could take to find the solution to the system of equations using the Elimination Method?

Multiply by -1 through one equation to flip the signs and create opposite y-values.

Multiply by -1 through one equation to flip the signs and create opposite x-values.

Multiply by 1 through one equation to flip the signs and create opposite y-values.

Isolate a variable and substitute the value in the other equation.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

David is running a concession stand at a soccer game. He sells nachos and sodas. Nachos cost $1.50 each and sodas cost $0.50 each. At the end of the game, David made a total of $78.50 and sold a total of 87 nachos and sodas combined. Which system of equations represents this situation?

1.5x+0.5y=78.5
x+y=87

1.5x+0.5y=78.5
1.5x+0.5y=87

x+y=78.5
1.5x+0.5y=87

x+y=78.5
x+y=87

Tags

CCSS.HSA.CED.A.3

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Alexandra finds that she can give 3 haircuts and 2 hair dyes in 315 minutes. Giving 2 haircuts and 4 hair dyes takes 450 minutes.  Which system of equations represents the situation?

3x + 2y = 315
2x + 4y = 450

3x + 2y = 450
2x + 4y = 315

2x + 2y = 315
3x + 4y = 450

Tags

CCSS.HSA.CED.A.3

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

How many solutions?

One Solution

No solution

Infinitely Many Solutions

Tags

CCSS.8.EE.C.8B

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Solve for x and y
2x − 3y = −1
 y = x − 1

(-2,-3)

(0,-1)

(3,4)

(4,3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Solve by elimination 
-2x+6y= 16
-4x-3y= 2

(2,2)

(-2, -2) 

(-2,2)

(2,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

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