There are 15 animals in a barn. These animals are horses (x) and chickens (y). There are 44 legs in all. Which system of equations represents the situation?
Solving Systems of Equations Using Word Problems

Quiz
•
Mathematics
•
9th Grade
•
Hard
Anthony Clark
FREE Resource
20 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
x + y = 15
4x + 2y = 44
4x + 2y = 15
x + y = 44
x = 2y + 44
4x = y + 15
2x - 4y = 44
x - y = 15
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Nancy went to the grocery story. On Monday she purchased 4 apples (x) and 6 bananas (y) for a total of $13. On Wednesday she purchased 3 apples and 7 bananas for a total of $13.50. Which system of equations represents the situation?
4x + 6y = 3
13.5x - 13y = 6
x + y = 4
x - y = 6
4x + 6y = 13
3x + 7y = 13.5
4x - 6y = 13
3x - 7y = 13.5
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
David is running a concession stand at a soccer game. He sells nachos and sodas. Nachos cost $1.50 each and sodas cost $0.50 each. At the end of the game, David made a total of $78.50 and sold a total of 87 nachos and sodas combined. Which system of equations represents this situation?
(35, 52)
(18, 69)
( 52, 35)
(61, 26)
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
On the first night, the Movie House Theater sold 7 adult tickets and 11 child tickets for $227. On the second night they took in $150 by selling 6 adult tickets and 6 child tickets. Find the price of an adult ticket and the price of a child ticket.
Adult $13
Child $5
Adult $10
Child $6
Adult $8
Child $16
Adult $12
Child $13
5.
DROPDOWN QUESTION
1 min • 1 pt
There were (a) students in each van and (b) students in each bus.
7
28
15
30
8
9
45
10
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which system of equations is correct?
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The talent show committee sold a total of 530 tickets in advance. Student tickets cost $3 each and the adult tickets cost $4 each. If the total receipts were $1740, which system could be used to find how many of each type of ticket were sold?
S + A = 530
3S + 4A = 1740
S + A = 530
4S + 3A = 1740
S + A = 1740
3S + 4A = 530
S + A = 1740
4S + 3A = 530
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