Solving Linear Equations by Using Substitution

x = 3y -13

4x + 2y = 4

• (1, 4)

• (-1, -4)

• (-1, 4)

• (1, -4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve:

x = -3y - 17

2x + 3y = -7

• (1, -20)

• (3, 0)

• (-5, -2)

• (10 , -9)

Tags

CCSS.HSA.REI.C.6

CCSS.8.EE.C.8B

Solve the system of equations.

• (-6, 1)

• (1, -6)

• No solution

• Infinite solutions

Tags

CCSS.8.EE.C.8B

6x + y = -1

y = -3x - 4

• (3, 1)

• (1, 7)

• (-3, 1)

• (1, -7)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• (4, -3)

• (-1, -3)

• (-4, -3)

• (-4, 3)

Tags

CCSS.HSA.REI.C.6

CCSS.8.EE.C.8B

What is the final step to solve a system with substitution?

• Substitute the values found from the previous step into one of the original equations and solve for the remaining variable

• Solve the linear system for both its variables

• Solve one equation for one of its variables

• Solve one equation for one of its variables

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system by using the substitution method

• (3,6)

• (6,3)

• (1,4)

• (4,1)

Tags

CCSS.HSA.REI.C.6

CCSS.8.EE.C.8B

Solve the following systems of equations using substitution:

2y + x = -15

x = 3y

• (-3,-9)

• (-9,-3)

• (-3,9)

• (9,-3)

Tags

CCSS.HSA.REI.C.6

CCSS.8.EE.C.8B

Solve the system of equations using the substitution method

• (-2,6)

• (6,-2)

• (-2,4)

• (4,-2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the first step to solve a system with substitution?

• Substitute the values found from the previous step into one of the original equations and solve for the remaining variable

• Solve the linear system for both its variables

• Solve one equation for one of its variables

• Substitute the expression from the previous step in the other two equations to obtain a linear system in two variables

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6