Systems of Equations - Substitution

Solve the system given using the substitution method.

y = 3x - 7

2x + y = 3

• (-1,2)

• (5,4)

• (4,5)

• (2,-1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system using the substitution method.

y = 3x - 13

2x + 4y = 4

• (5,2)

• (4, -1)

• (-4, -1)

• (5, -2)

• (-4, 1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system using the substitution method

y = 5x − 5

y = −4x + 22

• (1, 2)

• (3, 10)

• (-1, 2)

• (-3, 10)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the solution to the system?
8x + 4y = 12
y = -2x + 3

• (0,3)

• (3,0)

• No solution(parallel lines)

• Infinitely many solutions

Tags

CCSS.8.EE.C.8B

Solve the system of equations by substitution.
y = -4x + 5
y =  3x - 16

• (-3, -25)

• (3,-7)

• (11, 17)

• (21, 47)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following systems of equations using substitution:

2y + x = -15

x = 3y

• (-3, -9)

• (-9, -3)

• (-3, 9)

• (9, -3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve for x and y by using the substitution method.

y = -2x

4x - y = 0

• (1,2)

• (0,0)

• No Solutions

• Infinite Solutions

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve this system by substitution.

• (1, -4)

• (1, 4)

• (-4, -7)

• (-7, -4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

2x - 3y = -1

y = x - 1

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = -3x + 5

5x - 4y = -3

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6