
Systems of Linear Equation Pairs
Authored by Anthony Clark
Mathematics
9th Grade
CCSS covered

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20 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
two or more linear equations with the same variables
piecewise defined function
linear inequality
solution to a linear inequality
boundary line
system of linear equations
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A method to solve a system. One equation is solved for one of the variables then the expression for that variable is substituted into the other equation
substitution method
elimination method
coincident lines
parallel lines
slope intercept form
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A method to solve a system. Two equations are combined to eliminate one variable.
substitution method
elimination method
coincident lines
parallel lines
slope intercept form
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Lines that occupy the same location, pass through the same set of ordered pairs and intersect infinitely many times.
substitution method
elimination method
coincident lines
parallel lines
slope intercept form
Tags
CCSS.8.EE.C.8A
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Find the solution to the system of equations: 4x - 3y = 5 and 2x + 7y = 1
x = 2, y = -1
x = -1, y = 2
x = 5, y = 3
x = 3, y = 4
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Find the solution to the system of equations: 4x - 3y = 5 and 2x + 7y = 1
x = 2, y = -1
x = -1, y = 2
x = 5, y = 3
x = 3, y = 4
Tags
CCSS.HSA.REI.C.9
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A customer at a store paid $64 for 3 large candles and 4 small candles. At the same store, a second customer paid $68 for 1 large candle and 8 small candles. The price of each large candle is the same, and the price of each small candle is the same. Which system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y?
4y = 3x + 64
8y = x + 68
4y = 3x + 64
8y = x + 60
3x + 4y = 64
x + 8y = 68
3x + 4y = 64
x + 8y = 60
Tags
CCSS.HSA.CED.A.3
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