Standard Form Vertex

Write the given equation in vertex form:

y=x²+6x-2

• y=(x+3)²+7

• y=(x+3)²-11

• y=(x+6)²-2

• y=(x-3)²-38

Write the given equation in vertex form:

y=x²+10x-5

• y=(x+10)²-105

• y=(x+5)²+25

• y=(x+5)²+20

• y=(x+5)²-30

Write the given equation in vertex form:

y=x²+16x+100

• y=(x+8)²+36

• y=(x+8)²-36

• y=(x-8)²+164

• y=(x+8)²

Write the given equation in vertex form:

y=x²-10x+10

• y=(x-10)²+10

• y=(x+5)²+35

• y=(x-5)²+15

• y=(x-5)²-15

• A
• B
• C
• D

To find the vertex of a quadratic in standard form, you ​ (a)   and ​ (b)   . Then you ​ (c)   the value back into the ​ (d)   to find the ​ (e)   coordinate of the vertex.

• take the opposite of b

• divide it by 2

• substitute

• equation

• y

• x

• take the opposite of c

• multiply it by 5

• A
• B
• C
• D

Convert the equation from vertex form to standard form.

• y = -5x² - 20x - 30

• y = -5x² - 4x - 10

• y = 25x² + 100x + 90

• y = 25x² - 10x - 30

Convert this equation in vertex form to standard form.

• x² -2x - 2

• x²+x-2

• x²+2

• x²-2x