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Solve Exponential Growth and Decay

Authored by Anthony Clark

Mathematics

9th Grade

CCSS covered

Solve Exponential Growth and Decay
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11 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the a-value (or y-intercept) for the function: f(x) = 800(0.85)x?

800

0.85

0.15

x

Tags

CCSS.HSF-IF.C.7E

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the decay rate for the function: f(x) = 800(0.85)x?

800

0.85

15%

x

Tags

CCSS.HSF-IF.C.8B

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The value of a car is $15,000 and depreciates at a rate of 8% per year. What is the exponential equation that models this situation?

y = 8(15,000)x

y = 15,000(1.08)x

y = 15,000(0.92)x

y = 15,000(0.08)x

Tags

CCSS.HSF.LE.A.2

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The equation f(x) = 300(1.06)x is being used to calculate the amount of money in a savings account.  What does the 1.06 represent?

6% growth

6% decay

1.06% growth

.06% decay

Tags

CCSS.HSF-IF.C.8B

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Determine if the equation y = 15(1.35)x represents exponential growth or decay and justify. Hint: Think about the growth and decay equations.

Growth, because the scale factor is greater than 1

Growth, because the scale factor is less than 1

Decay, because the scale factor is greater than 1

Decay, because the scale factor is less than 1

Tags

CCSS.HSF-IF.C.8B

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Write an exponential function to model the situation. Then solve. The value of a car is $18000 and is depreciating at a rate of 12% per year. What will the value of the car be after 10 years?

V(t) = 18000(.88)t ; $12986.98

V(t) = 18000(.12)t ; $12986.98

V(t) = 18000(.88)t ; $5013.02

V(t) = 18000(.12)t ; $5013.02

Tags

CCSS.HSF.LE.A.2

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The value of a car is $15,000 and depreciates at a rate of 8% per year. What is the decay factor?

0.08

1.08

0.92

8

Tags

CCSS.HSF-IF.C.8B

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