Statistics Confidence Interval

Quiz
•
Mathematics
•
12th Grade
•
Hard
Anthony Clark
FREE Resource
20 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
In a survey of 104 students, it was found that 79 went to the homecoming game this year. Calculate a 99% confidence interval for p.
(0.652, 0.868)
(0.691, 0.829)
(0.678, 0.842(
(0.685, 0.895)
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
In a survey of 104 students, it was found that 79 went to the homecoming game this year. A 99% confidence interval for p is (0.652, 0.868). Interpret this interval.
99% of the time the true proportion of people who went to the homecoming game this year is between 65.2% and 86.6%.
The probability that the population proportion of people who went to the homecoming game this year is between 65.2% and 86.6% is 95%.
Based on this sample, I am 99% confident that the true proportion of people who went to the homecoming game this year is between 65.2% and 86.6%.
99% of all possible intervals calculated this way will capture the true proportion of people who went to the homecoming game this year
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
If 827 represents "no" voters out of 2584, construct a 95% confidence interval for the "no" group.
[.300,.340]
[.298,.342]
[.302,.338]
[.288,.352]
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Identify the confidence interval used in the figure below if each shaded area is equal to 0.05.
90%
95%
98%
99%
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A recent survey found that out of 400 random American adults, 89% pay their bills on time. The margin of error in this survey was 2%. What is the interval of values in which the truth is likely found?
89% - 91%
87% - 89%
87% - 91%
388 - 402
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
7.
DRAG AND DROP QUESTION
1 min • 2 pts
A 95% confidence interval was conducted on American adults aged 45-64 and found that the between 15.7% and 19.4% had diabetes as of 2016. a) What is the population proportion that has diabetes according to this confidence interval? (a) b) What was the margin of error associated with this data? (b)
17.55%
1.85%
11.55
5.775
11.55%
5.775%
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