Distinguishable Permutation and Combination

Suppose that in a certain association, there are 12 elected members of the Board of Directors. In how many ways can a president, a vice president, a secretary, and a treasurer be selected from the board?

• 11 880 possible ways

• 10 880 possible ways

• 11 990 possible ways

• 10 990 possible ways

Roxanne has three vases of the same kind and two candle stands of the same kind. In how many ways can she arrange these items in a line?

• permutation with different objects

• distinguishable permutation

• circular permutation

15. In a school club, there are 7 possible choices for the president, a secretary, a treasurer, and an auditor. Assuming that each of them is qualified for any these positions, in how many ways can the 4 officers be elected?

• permutation with different objects

• distinguishable permutation

• circular permutation

16. How many different 9 letter words (real or imaginary) can be formed from the letters in the word COMMITTEE?

• permutation with different objects

• distinguishable permutation

• circular permutation

19. Find the number of permutations of the letters of the word ODD?

• permutation with different objects

• distinguishable permutation

• circular permutation

20. In how many ways can 6 people arrange themselves in a row for a picture-taking?

• permutation with different objects

• distinguishable permutation

• circular permutation

What do you call an arrangement of things in a definite order or the ordered arrangement of distinguishable objects without allowing repetitions among the objects?

• Area

• Combination

• Circumference

• Permutation

Find the number of distinguishable permutation of the letter in a word “BASKETBALL“.

• 453, 600 ways

• 45, 360 ways

• 4,536 ways

• 453 ways

In how many ways can 2 red marbles and 4 blue marbles be arranged in a row?

• 48

  ways

• 90 ways

• 720 ways

• 1,300 ways

 

Calculate the number of ways how 4 different prizes can be given to 4 participants of a quiz.

• 24

• 16

• 20

• 12