A recent study of 750 Internet users in Europe found that 35% of Internet users were women. What is the 95% confidence interval of the true proportion of women in Europe who use the Internet?
Proportion Confidence Intervals Interpretation

Quiz
•
Mathematics
•
12th Grade
•
Hard
Anthony Clark
FREE Resource
20 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
0.321 < p < 0.379
0.316 < p < 0.384
0.309 < p < 0.391
0.305 < p < 0.395
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A survey of 800 women shoppers found that 17% of them shop on impulse. What is the 98% confidence interval for the true proportion of women shoppers who shop on impulse?
0.148 < p < 0.192
0.136 < p < 0.204
0.144 < p < 0.196
0.139 < p < 0.201
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
It was found that in a sample of 90 teenage boys, 70% of them have received speeding tickets. What is the 90% confidence interval of the true proportion of teenage boys who have received speeding tickets?
(0.621, 0.780)
(0.591, 0.812)
(0.584, 0.830)
(0.615, 0.805)
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which of the following actions would produce a confidence interval with a smaller width assuming all other contingencies remained constant?
Using a higher confidence level
Using a lower confidence level
5.
MULTIPLE CHOICE QUESTION
1 min • 2 pts
A 90% confidence interval for the proportion difference p1-p2 was calculated to be (0.247, 0.325). Which of the following conclusions is supported by the interval?
There is evidence to conclude that p1>p2 because 0.325 is greater than 0.247.
There is evidence to conclude that p1<p2 because 0.325 is greater than 0.247.
There is evidence to conclude that p1>p2 because all values in the interval are positive.
There is evidence to conclude that p1<p2 because all values in the interval are positive.
There is evidence to conclude that p2>p1 because 0.247 and 0.325 are both greater than 0.05.
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
There is a 0.95 probability that the proportion of all residents in the town who favor the proposal will be between 0.361 and 0.579.
The probability that 95 percent of the residents in the town will favor the proposal is between 0.361 and 0.579.
We are 95 percent confident that any sample of 83 residents will produce a sample proportion between 0.361 and 0.579.
We are 95 percent confident that the proportion of all residents in the sample who favor the proposal is between 0.361 and 0.579.
We are 95 percent confident that the proportion of all residents in the town who favor the proposal is between 0.361 and 0.579.
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
In a survey of 104 students, it was found that 79 went to the homecoming game this year. A 99% confidence interval for p is (0.652, 0.868). Interpret this interval.
99% of the time the true proportion of people who went to the homecoming game this year is between 65.2% and 86.6%.
The probability that the population proportion of people who went to the homecoming game this year is between 65.2% and 86.6% is 95%.
Based on this sample, I am 99% confident that the true proportion of people who went to the homecoming game this year is between 65.2% and 86.6%.
99% of all possible intervals calculated this way will capture the true proportion of people who went to the homecoming game this year
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