Solving Systems of Equations with Elimination

Solve by elimination
4x-6y= -6
-2x-12y= -12

• (0,1) 

• (1,0)

• (1,1)

• (2,1)

Solve by elimination
-12x-4y= -8 
  -6x-2y= -4

• no solution 

• (0,0)

• infinite solutions 

• (4,0)

4x + 8y = 20
−4x + 2y = −30

• (-1, 7)

• (-7, 1)

• (7, -1)

• (1, -7)

x − y = 11
2x + y = 19

• (-1, 10)

• (30, 19)

• (19, 30)

• (10, -1)

5x + y = 9
10x − 7y = −18

• (4, -11)

• (1, 4)

• (-1, 14)

• (-4, 29)

Solve the system by elimination.  

4x + 12y = −1
−3x − 9y = 0 

• (10, 1) 

• (−10, −1) 

•  (10, −1) 

•  No solution 

8x + 14y = 4
-6x - 7y = -10

• (4, -2)

• (-2, 4)

• (0, 3)

• (4, -2)

-x - 7y = 14
-4x - 14y = 28

• (-2, 0)

• (0, -2)

• (-2, -2)

• (0, 2)

Will the solution (-3, -7) make the following system of equations a true statement? 
y = 4x + 5
y = x – 4

• YES

• NO

What is the solution to the system?

• (0, 3)

• (1, -1)

• (-3, 1)

• (1, 3)