Two Step Equations Final
Authored by Anthony Clark
Mathematics
8th Grade
CCSS covered
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14 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
FOLLOW THE STEPS!!
Solve the system of equations:
x = 2
4x + 8 = y
1. Substitute x for 2 in the 2nd equation
2. Add the numbers.
3. Your answer is (x,y)
(2, 16)
(2, 6)
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
FOLLOW THE STEPS!!
Solve the system of equations:
y = 2
x + y = 2
1. Substitute y for 2 in the 2nd equation
2. Subtract 2 from both sides
3. Your answer is (x,y)
(0, 2)
(2, 2)
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
FOLLOW THE STEPS!!
Solve this systems of equations
x + y = 7
y = 4
1. Substitute y for 4 in the second equation
2. Subtract 4 from both sides
Your answer is (x,y)
(3,4)
(-1, 4)
No solution
Infinite solutions
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the first step in solving this equation for x?
2x + 2 = 6
Subtract 2 from both sides
Add 2 to both sides
Tags
CCSS.7.EE.B.4A
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
FOLLOW THE STEPS!
Solve the system by substitution.
2x - y = 7
y = 3
1. Plug 2 into the 1st equation 2x - 3 = 7
2. Add 3 to both sides
3. Divide by 2
Answer is (x,y)
(5,3)
(8,3)
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Jacob solved the following equation using the steps shown.
Step 1 5x + 9 = 2x - 3
Step 2 3x + 9 = -3
Step 3 3x = -12
Step 4 x = -4
What operation did he perform to get from Step 1 to Step 2?
Subtracted 2x from both sides of the equation
Subtracted 9 from both sides of the equation
Multiplied both sides of the equation by 3
Added -3 to both sides of the equation
Tags
CCSS.HSA.REI.A.1
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the first step to solve this equation:
11 - 3x = 44
Add 3 to both sides
Subtract 11 from both sides
Add 11 to both sides
Divide 3 on both sides.
Tags
CCSS.7.EE.B.4A
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