Exponential Word Problems Compounding

Solve the problem: Mrs. Madison has discovered she likes to crochet. She went out an bought 7 skeins of yarn to start her collection. That collection has doubled each month. How many skeins of yarn would she have after 6 months?

• 512 skeins

• 448 skeins

• 98 skeins

• 235,298 skeins

Write an equation for this problem:

A population of 1200 bacteria is doubling each day for x days.

What would be the "a" value (initial value) for this problem? A local zoo has a population of 32 meerkats. They are doubling every 5 years. How many would there be in 10 years?

• 32

• 2

• 5

• 10

What would be the "b" value (multiplier) for this problem?

A local zoo has a population of 32 meerkats. They are doubling every 5 years. How many would there be in 10 years?

• 32

• 2

• 5

• 10

Write an equation that models the following situation: Samantha's hair was known to grow very rapidly. It began at a length of 6 in and grew at a rate of 14% a week. (HINT: Write out the equation on a separate piece of paper and hen simplify inside the parenthesis)

• y=6(0.14)^x

• y=6(1+14)^x

• y=6(1.14)^x

• y=6(0.86)^x

James' 70 in. giant peach doubles in size every week. Write an expression that would represent how big the peach is after 5 weeks.

• y = 70(2)³⁵

• y = 70(2)⁵

• y = 2(70)⁵

• y = 5(70)²

Write an equation that models the following situation:
Samantha's hair was known to grow very rapidly. It began at a length of 6 in and grew at a rate of 14% a week.

• y=6(0.14)^x

• y=6(1 + 14)^x

• y=6(1 + .14)^x

• y=6(0.86)^x

Which of the following functions shows an initial amount of $15 and an increase of 35% each year?

• y = 15(35)^x

• y = 15(1.35)^x

• y = 15(0.35)^x

• y = 35(1.15)^x

Suppose a culture of bacteria begins with 5000 cells and dies by 30% each year. Write an equation that represents this situation.

• y=5000(0.7)^x

• y=30(5000)^x

• y=5000(1.3)^x

• y=5000x^x

You have inherited land that was purchased for $30,000 in 1960. The value of the land increased by approximately 5% per year. What is the approximate value of the land in the year 2011?

• $361,223.09

• $15,000.00

• $31,500.29

• $280,500.86