Transformations of Absolute Value Equations

Transformations of Absolute Value Equations

11th Grade

20 Qs

quiz-placeholder

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Transformations of Absolute Value Equations

Transformations of Absolute Value Equations

Assessment

Quiz

Mathematics

11th Grade

Hard

CCSS
HSF-IF.C.7D

Standards-aligned

Created by

Anthony Clark

FREE Resource

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Describe the transformation of the equation below from the parent function of y = I x I
y = -2 I x - 3 I + 3

reflected over x axis, stretched by 2, right 3, up 3

reflected over x axis, stretched by 2, left 3 up 3.

reflected over x axis, shrunk by 2, right 3, up 3

reflected over the x axis, shrunk by 2, left 3, up 3

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Describe the transformations of the absolute value equation.

Reflects over x-axis, compresses wider, shifts right 1 unit

Reflects over x-axis, compresses wider, shifts up 1 unit

Reflects over x-axis, stretches more narrow, shifts right 1 unit

Reflects over x-axis, stretches more narrow, shifts up 1 unit

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image


The blue graphs is the parent function f(x)=|x|, the red must be

g(x)=|x+2|

g(x)=|x|+2

g(x)=|x-2|

g(x)=|x|-2

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Describe the transformation that is applied to the parent function. 
f(x) = IxI -5

Shifts left 5

Shifts right 5

Shifts up 5

Shifts down 5

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

y=|x−3|−1

A

B

C

D

Tags

CCSS.HSF-IF.C.7D

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Describe the transformations of the absolute value equation.

Flips to A shape, compresses wider, shifts right 1 unit

Flips to A shape, compresses wider, shifts up 1 unit

Flips to A shape, stretches more narrow, shifts right 1 unit

Flips to A shape, stretches more narrow, shifts up 1 unit

7.

MATCH QUESTION

1 min • 4 pts

State the RANGE of the absolute value function given the following transformations:

y = |x + 2| + 7 

y = -|x - 2| + 7

y = -|x - 2| - 7

y = |x - 2| - 7 

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