George Mitchell Solving Quadratics by Factoring

Solve:

k² - 2k - 24 = 0

• k = -4, 6

• k = -4, -6

• k = -6, 1

• k = 4, -6

Solve:

3x² + 18x +15 = 0

Hint: Factor GCF first.

• x = 3, 2

• x = 5, 1

• x = -5, -1

• x = -3, -2

Solve
x² + 2x - 24 = 0

• x = -6, x = 4

• x = 6, x = -4

• x = 12, x = -2

• x = 8, x = -3

Solve
x² + 9x + 20 = 0

• x = -2, x = -10

• x = -3, x = -4

• x = -4, x = -5

• x = -4, x = -6

Solve
x² + 7x + 12 = 0

• x = -2, x = -10

• x = -3, x = -4

• x = -4, x = -5

• x = -4, x = -6

Solve
x² + 13x + 12 = 0

• x = -1, x = -12

• x = -1, x = -24

• x = -2, x = -6

• x = -2, x = -12

Solve
6x² + 17x + 12 = 0

• x = -4/3, x = -3/2

• x = 9, x = 8

• x = 4, x = 3

• x = -4, x = -3

Solve:
x² - 49 = 0

• x = -7, x = 7

• x = -7

• x = 7

• x = -7, x = 1

Solve
5x² - 28x + 32 = 0

• x = 10/3, x = -6

• x = 8, x = 4/5

• x = 8/5, x = 4

• x = 8/5, x = -7

What is the next step in solving after getting the quadratic in factored form?

• Plug in zero for x

• Multiply the binomials

• FOIL

• Set each binomial factor equal to zero