Solving Quadratics Zero Product

• 2 and 3

• -2 and -3

• 2 and -3

• -2 and 3

Tags

CCSS.HSA-REI.B.4B

• Yes, she factored correctly and then used the zero product property

• No, she didn't factor correctly so the rest of her work is wrong.

• No, she did not set the equation equal to zero before factoring.

Tags

CCSS.HSA-REI.B.4B

• A
• B
• C
• D

Tags

CCSS.HSA-REI.B.4B

• A
• B
• C
• D

Tags

CCSS.HSA-REI.B.4B

• -4, 2
• -2, 4
• -16
• -4

Tags

CCSS.HSA-REI.B.4B

• A
• B
• C
• D

Tags

CCSS.HSA-REI.B.4B

Find the zeros of this quadratic. (Solutions)

• b=4/5, b=3

• b=4, b=-3

• b=1/5, b=3

• b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B

Find the zeros of this quadratic.

• b=4/5, b=3

• b=4, b=-3

• b=1/5, b=3

• b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B

What are the zeros of the function below?
(x - 6)(2x + 4) =0

• x = -6, x = -4

• x = 6, x = -2

• x = 4, x = 6, x =2

• cannot be determined

Tags

CCSS.HSF-IF.C.7C

Solve

• b=4/5, b=3

• b=4, b=-3

• b=1/5, b=3

• b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B