Solving Quadratic Equations by Factoring

Solve 2x² - 7x + 6 = 0 by factoring

• x = -3/2 and x = -2

• x = -3 and x = -2

• x = 3 and x = 2

• x = 3/2 and x = 2

Tags

CCSS.HSA-REI.B.4B

The solutions of the quadratic equation 
x²+5x+6=0 are

• x= -3 or x = -2

• x = -6 or x = 1

• x = 3 or x = 2

• x = -3 or x = 2

Tags

CCSS.HSA-REI.B.4B

Convert x²-9x+20 to factored form and solve.

• (x-10)(x+2); x=-2, 10

• (x+4)(x+5); x=-5, -4

• (x-4)(x-5); x=4, 5

• Not factorable

Tags

CCSS.HSA-REI.B.4B

• ± 1
• ± 4/3
• ± 3/4
• No real solution

Tags

CCSS.8.EE.A.2

The solutions of the quadratic equation 
x²+2x-15=0 are

• x = 3 or x = 5

• x = 5 or x = -3

• x = -5 or x = 3

• x = -3 or x = -5

Tags

CCSS.HSA-REI.B.4B

Solve by factoring:  2x²+ 7x + 6 = 0

• x= 3/2 and x = 2

• x = -3/2 and x = -2

• x = 6 and x = 7

• x = -6 and x = -7

Tags

CCSS.HSA-REI.B.4B

Solve by factoring:
x² - 9x = 0

• 9

• 0, 9

• -9, 0

• -9

Tags

CCSS.HSA-REI.B.4B

Solve by factoring: x² = 7x + 18

• -7 and -18

• 9 and 2

• 9 and -2

• 2 and 7

Tags

CCSS.HSA-REI.B.4B

Solve for x:

(x-5)(x+6)=0

• {5,5 }

• { -5,-5 }

• { -5,-6 }

• {5,-6 }

Tags

CCSS.HSA-REI.B.4B

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x

• Solve for x

• FOIL

• Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B