Parabola with Focus and Directrix

The focus is always inside the parabola.

• true

• false

(y-4)² = -8(x+1)
What are the coordinates for the focus?

• (1,4)

• (-1,6)

• (-1,2)

• (-3,4)

(x+3)² = 4(y+5)
What is the equation of the directrix?

• x = 4

• x = 2

• y = -4

• y = -6

What is the equation of a parabola with focus (9, 5) and directrix y = 1?

• 8(x - 9) = (y - 3)²

• 8(y - 3) = (x - 9)²

• 16(x - 9) = (y - 3)²

• 16(y - 3) = (x - 9)²

Tags

CCSS.HSG.GPE.A.2

If the directrix is y = 4 and the focus is at 
(3, 0), the equation of the parabola is:

• y = (-1/8)(x - 3)² + 2

• x = (-1/8)(y - 2)² + 3

• y = (1/8)(x - 3)² + 2

• x = (1/8)(y - 2)² + 3

Find the focus and the directrix. \(x=y^2\)

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Identify the focus and directrix of the parabola: (y-2)² = 24(x-5)

• focus: (5, 7); directrix: y = -4

• focus: (5, -4); directrix: y = 7

• focus: (11, 2); directrix: y = -1

• focus: (-1, 2); directrix: y = 11

Find the focus and the directrix.

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Write the equation of the parabola given that the Focus is (0, 6) and the Directrix is y = - 6.

Tags

CCSS.HSG.GPE.A.2

If the directrix is y = 4 and the focus is at 
(3, 0), the value of p is:

• 8

• -8

• 2

• -2