Solving X in Logarithm

log₂(2) + log₂(8x) = 6

• x = 3

• x = 2

• x = 6

• x = 4

log₉(x)+log₉(x+2)=log₉(35)

• 5

• -7

• 5, -7

• -7, -13

Solve log₁₀(x) + log₁₀(x+3) = 1

• 5

• -2

• -5

• 2

First step to solve for x: 8^x+1= 3

• Rewrite as the same base

• take logarithm of both sides and distribute the x+1

First step to solve: log (x) + log (x) = log (25)

• get rid of the log and have x+x=25

• Condense the left to log(x*x)=log(25) then set equal

• condense to log(2x)=log(25)

log (4x − 5) = log (2x − 1) 

• Set 4x-5 = 2x-1

• use the circle rule

• condense

log₂(x + 2) + log₂x = 3

• set x+2+x=3

• condense by multiplying (x+2)*x and then use circle rule

• condense bby adding x+2 and x and then setting equal to 3

First step to Solve log₁₀(x) + log₁₀(x+3) = 1

• drop the log and write x+x+3=1

• condense by multiplying x and x+3 and then using circle rule

First step to solve log₂(x+3)=4

• circle rule 2^4=x+3

• set x+3=4

• distribute the 2 to x+3

Tags

CCSS.HSF.BF.B.5

First step to Solve log₇x-log₇3=2

• drop the log and write x-3=2

• condense by dividing x/3 and then setting equal to 2

• condense by dividing x/3 and then using the circle rule