Quadratic Velocity Problems

Quadratic Velocity Problems

9th Grade

15 Qs

quiz-placeholder

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Quadratic Velocity Problems

Quadratic Velocity Problems

Assessment

Quiz

Mathematics

9th Grade

Hard

CCSS
HSF.IF.B.4

Standards-aligned

Created by

Anthony Clark

FREE Resource

15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Jason launched a rocket for a physics experiment. This equation can be used to find the height (h), in feet, of the rocket after t seconds. h = -16t2 + 288t + 8 How many seconds will it take for the rocket to reach a height of 1,304 feet?

9.0 seconds

9.6 seconds

81.0 seconds

82.0 seconds

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

If each mark on the x-axis represents one second, when did the object reach the ground?

2.5 seconds

6 seconds

5.5 seconds

5 seconds

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

An object in launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. Its height is represented by the equation s(t) = –16t2 + 64t + 80. What will be the object's maximum height? 

2 ft

80 ft

144 ft

64 ft

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The function f(t) = -5t2+20t + 60 models the approximate height of an object t seconds after it is launched. How many seconds does it take the object to hit the ground? 

4 seconds

-2 seconds

-6 seconds

9 seconds

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The height of a water balloon that is launched into the air is given by h(t) = -5x2+20x+25. When will the balloon explode on the ground?

5 seconds

1 second

2 seconds

3 seconds

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The height of a water balloon that is launched into the air is given by h(t) = -5t2 + 40t + 2. From what height was the balloon released?

2 meters

5 meters

40 meters

20 meters

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

If a toy rocket is launched vertically upward from ground level with an initial velocity of 128 feet per second, then its height h after t seconds is given by the equation

h(t) = -16t2 +128t

When will the object reach its maximum height?

4 ft

0 seconds

0 ft

4 seconds

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