Substitution to Solve Simple Algebraic Equations

What is the solution to this system?
2x + 3y = 4
y= 5x - 27

• (5,-2)

• (5, 2)

• (2,3)

• (3,2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Which answer has a correct first step for this system:

• The variable is already isolated, so we've already solved the system.

• The variable is already isolated for y, so we substitute it in the first equation and solve for x

  3x + 3(3x + 5) = 3

• Free sha vaca doo

• The variable is already isolated for y, so we substitute it in the second equation and solve for x

  y = 3(3x + 3y) = 3

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve this system using substitution

y = 3x - 5

2x + 4y = -6

• (1, -2)

• (2, -2)

• (1, 2)

• Why have you done this?

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve with substitution

x = -3y - 8

x - 2y = -3

• (5, -1)

• (-5, 1)

• (-5,-1)

• (1,-5)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations.

• (-34, -17)

• (8, 4)

• (10, 20)

• No solution

• Infinite solutions

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

w + 12 = 20

• w = 32

• w = -32

• w = 8

• w = -8

Tags

CCSS.6.EE.B.7

3x = 36

• x = 18

• x = 12

• x = 6

• x = 33

Tags

CCSS.6.EE.B.7

^x/₄ = 2

• x = 8

• x = 2

• x = 0.5

• x = 6

Tags

CCSS.6.EE.B.7

x - 8 = -5 

• x = 13

• x = -13

• x = 3

• x = -3

Tags

CCSS.6.EE.B.7

x - 5.5 = 10.5

• x = 15

• x = 14

• x = 16

• x = 15.5

Tags

CCSS.6.EE.B.7