Polynomial Zeros and Factors

0=x³+11x²+24x

• x=8,3

• x=-8,-3

• x=-8,-3,0

• x=0, 8, -3

Solve by factoring: x² - 9x + 20 = 0

• x = -4 and x = -5

• x = 20 and x = -9

• x = 4 and x = 5

• x = -4 and x = 5

Solve by factoring:  2x³+ 7x² + 6x = 0

• x=0, x= 3/2 and x = 2

• x=0, x = -3/2 and x = -2

• x=0, x = 6 and x = 7

• x=2, x = -6 and x = -7

f(x)= x²(x – 2)³(x – 7)

State the zeros, include multiplicity.

• 0 (Mult of 2), 2 (Mult of 3), 7 (mult 1)

• 2 (Mult of 3), 7 (mult 1)

• 0, 2, 7

• 2 (mult of 2), 7 (mult of 3)

Write a polynomial function of least degree with integral coefficients that has the given zeros.

• A

• B

• C

• D

Find the zero(s) of the function.

• x = 1

• x = -3

• x = {-1, 3}

• x = 2

State the zeros of the polynomial (include multiplicity):
f(x) = x(x+3)²(x - 2)

• x = 0, 3, 2

• x = 0, -3 (multiplicity of 2), 2

• -3, 2

• 0, 2 (multiplicity of 3)

Select polynomial whose zeros and degree are given.
Zeros: – 5(multiplicity of 3), 9(multiplicity of 2), – 2, 4 Degree: 7

• (x + 5)³(x - 9)²(x + 2)(x - 4)

• (x + 5)³(x - 9)²(x + 2)⁷(x - 4)⁷

• (x + 5)³(x - 9)²(x + 2)

• (x + 5)(x - 9)(x + 2)(x - 4)

Write a polynomial function of least degree in standard form given the following zeros/roots/solutions:

• A

• B

• C

• D

Find the polynomial that the degree of 3 and has zeros: x = 3, -1, 2

• (x-3)(x+1)(x-2)

• (x+3)(x-1)(x+2)

• Don't count this one because I need to study more and retake it.