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Taylor Polynomials

Authored by Anthony Clark

Mathematics

9th Grade

Used 1+ times

Taylor Polynomials
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11 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Fill in the General Form of a Taylor Polynomial with the correct pieces:

1=fn(c); 2=n!; 3=(x−c)1=f^n\left(c\right);\ 2=n!;\ 3=\left(x-c\right)  

1=fn(c); 2=n!; 3=x1=f^n\left(c\right);\ 2=n!;\ 3=x  

1=fn(0); 2=n!; 3=(x−c)1=f^n\left(0\right);\ 2=n!;\ 3=\left(x-c\right)  

1=n!; 2=fn(c); 3=(x−c)1=n!;\ 2=f^n\left(c\right);\ 3=\left(x-c\right)  

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Given f(1)=3; f'(1)=-2; f''(1)=4; f'''(1)=-12, the first four terms of the Taylor Polynomial for f(x) are

3−2(x−1)+2(x−1)2−2(x−1)33-2\left(x-1\right)+2\left(x-1\right)^2-2\left(x-1\right)^3  

3−2x+2x2−2x33-2x+2x^2-2x^3  

3−2(x−1)+4(x−1)2−12(x−1)33-2\left(x-1\right)+4\left(x-1\right)^2-12\left(x-1\right)^3  

3−2x+4x2−12x33-2x+4x^2-12x^3  

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

This is a third-degree Taylor polynomial for a function f about x = 1. What is the value of  f′′(1)f''\left(1\right)   ?

403\frac{40}{3}  

80

240

480

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Suppose a function f is approximated with a fourth-degree Taylor polynomial about x = 1. If ∣f(5)(x)∣<0.01\left|f^{\left(5\right)}\left(x\right)\right|<0.01  between x = 1 and x = 3, then the maximum error incurred using T4(x)T_4\left(x\right)  to compute f(3) is

2.667

0.266

0.026

0.002

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

The graph of the function f(x) is shown. Which of the following could be a portion of the graph of the Maclaurin polynomial of degree 13 for f(x)?

Media Image
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6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which of the following is the fourth-degree Taylor Polynomial for f(x)=xsin⁡xf\left(x\right)=x\sin x  about  x=0x=0  .

P4(x)=x−16x3+15!x5−17!x7P_4\left(x\right)=x-\frac{1}{6}x^3+\frac{1}{5!}x^5-\frac{1}{7!}x^7  

P4(x)=−x2+16x4P_4\left(x\right)=-x^2+\frac{1}{6}x^4  

P4(x)=x2−16x4P_4\left(x\right)=x^2-\frac{1}{6}x^4  

P4(x)=2x2−4x4P_4\left(x\right)=2x^2-4x^4  

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The coefficient of (x−π4)3\left(x-\frac{\pi}{4}\right)^3  in the Taylor series about π4\frac{\pi}{4}  of f(x)=cos⁡xf\left(x\right)=\cos x  is

312\frac{\sqrt[]{3}}{12}  

112\frac{1}{12}  

162\frac{1}{6\sqrt[]{2}}  

132\frac{1}{3\sqrt[]{2}}  

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