Substitution With Two Variables

Solve the system by using the substitution method

• (3,6)

• (6,3)

• (1,4)

• (4,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following systems of equations using substitution:

2y + x = -15

x = 3y

• (-3,-9)

• (-9,-3)

• (-3,9)

• (9,-3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations using the substitution method

• (-2,6)

• (6,-2)

• (-2,4)

• (4,-2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the first step to solve a system with substitution?

• Substitute the values found from the previous step into one of the original equations and solve for the remaining variable

• Solve the linear system for both its variables

• Solve one equation for one of its variables

• Substitute the expression from the previous step in the other two equations to obtain a linear system in two variables

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations using substitution:

-4x + 4y = 8

y = -2x - 10

• (-4, -2)

• (12, -34)

• (4, -18)

• (-2, -6)

• (-4, 6)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following systems of equations using substitution:

x = 6

y = 2x - 3

• (6, 6)

• (6, 9)

• (9, 6)

• (9, 9)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following system of equations: 5x - 4y = 3 and 2x + 3y = 8

• x = 4, y = 3

• x = 2, y = 1

• x = 3, y = 2

• x = 1, y = 5

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• (1, 2)

• (4, 1)

• (2, -1)

• No Solution

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

If x = -3, in the equation -2x + y = 15, what is y? Type in the number.

Solve for x and y using the substitution method.

• (4,1)

• (4,-1)

• (1,4)

• (-1,4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6