Solve Quadratic by Zero Product

Find the solution to the quadratic equation b²-36=0

• -6 and 6

• 6

• -6

• 36

Solve: (k+1)(k−5)=0

• k = 1, 5

• k = -1, -5

• k = -1, 5

• k = 1, -5

Suzie solves the equation below:
x² + 4x - 12 = 2
(x - 2)(x + 6) = 2, 
by setting x -2 = 0 and x + 6 = 0. 
Her solutions are x = 2 and x = -6.
Is Suzie correct? Why or why not?

• Yes, she factored correctly and then used the zero product property

• Yes, she factored correctly and then square rooted.

• No, she did factor correctly, but she can't use the zero product property as shown.

• No, she didn't factor correctly so the rest of her work is wrong. 

What does the zero property rule tells us?

• That y=0 for all quadratic equations

• That if the product is zero, one of more factors needs to equal to zero

• That the quadratic formula always equals to 0

Solve the equation using the zero product property.
(x- 9)(x + 3) = 0

• x = 3 or x = 9

• x = 3 or x = -9

• x + -3 or x = 9

• x = -3 or x = -9

What does it mean to "find the zeros" of a quadratic?

• Plug in 0 and solve the expression.

• Factor then set each factor equal to zero and solve to find x-intercepts

• Set the expression equal to zero and solve 

• Factor then set each factor equal to zero and solve to find y-intercepts

Find the zeros of this quadratic.

• b=4/5, b=3

• b=4, b=-3

• b=1/5, b=3

• b=4/5, b=-3

x²+4x-32=0

• x= -8, 4

• x= 8, -4

• x= -8, -4

Solve using the Zero-Product Property.

(x + 4)(x − 3) = 0

• x = 4 and x = −3

• x = 2 and x = 1

• x = −4 and x = 3

• x = −2 and x = 1

Solve using the Zero-Product Property (x −11)(5x + 1) = 0