Equation to Model Situation

Equation to Model Situation

9th Grade

18 Qs

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Equation to Model Situation

Equation to Model Situation

Assessment

Quiz

Mathematics

9th Grade

Hard

Created by

Anthony Clark

FREE Resource

18 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Bob has $150 in his savings account and saves $40 per month.  Which equation represents the amount Bob has in his account after x months?

y = 150 + 40

y = 40x + 150

y = 150x + 40

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A holiday meal costs $12.50 a person plus a delivery fee of $30.  Which equation represents the amount a holiday meal costs, including delivery, for x people?

y = 30 + 12.5x 

y = 12.5 + 30

y = 12.5 + 30x

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Easy Car Rental charges $8.50 an hour plus a rental fee of $25.50. Which equation represents the total charges for x hours?

y = 8.5 + 25.5

y = 25.5 + 8.5x

y = 8.5 + 25.5x

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A tennis tournament begins with 128 players. At the end of round one, there will be 64 players. There are 32 players at the end of round 2 and 16 players remaining after round 3. Write the equation that best models this situation.

y = -64x + 128

y = 0.5x + 128

y = 128(0.5)x

y = 128(2)x

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Write an exponential function to model the situation. The cost of tuition at a college is $12,000 and is increasing at a rate of 6% per year.

C(t) = 12000(.94)t

C(t) = 12000(1.94)t

C(t) = 12000(.06)t

C(t) = 12000(1.06)t

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The function y = 24,220 (0.85)x represents Mr. Bittle's investment in the stock exchange where x is measured in months.

Which statement is NOT true.

Mr. Bittle loses 85% of his investment monthly

Mr. Bittle initially invested $24,220

Each month Mr. Bittle loses 15% of his investment

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Write an exponential function to model the situation. You invest $1500. Your investment escalates at a rate of 3.5%.

B(t) = 1500(0.965)t

B(t) = 1500(1.035)t

B(t) = 1500(.035)t

B(t) = 1500(1.965)t

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