Electric Field Concept

A charged particle is placed in a uniform field of force. The direction of the force on the particle is opposite to the direction of the field.

• Field: electric ; Charge on particle: negative

• Field: electric ; Charge on particle: positive

• Field: gravitational ; Charge on particle: negative

• Field: gravitational ; Charge on particle: positive

Tags

NGSS.HS-PS2-4

NGSS.HS-PS3-5

Which diagram shows the electric field lines surrounding an isolated negative point charge?

• 
• 
• 
• 

A flat plate is positively charged and a curved plate is negatively charged.

Which diagram shows the electric field lines between the two plates?

• 
• 
• 
• 

Tags

NGSS.HS-PS2-4

The diagram shows an electron in a uniform electric field.

In which direction will the field accelerate the electron?

• A

• B

• C

• D

Tags

NGSS.HS-PS2-1

NGSS.HS-PS3-5

Which statement about electric charges in a uniform electric field is NOT correct?

• Electric charges of the same magnitude, whether positive or negative, experience the same magnitude of force when placed in the same uniform electric field.

• The direction of the force on a positive charge placed in a uniform electric field is independent of the magnitude of the charge.

• The magnitude of the force on a positive charge placed in a uniform electric field is proportional to the magnitude of the electric field strength.

• The work done to move a positive charge a certain distance in a uniform electric field is independent of the direction of the movement.

Tags

NGSS.HS-PS3-5

A uniform field is where the electric field strength is ____________ at all points in the field.

• same

• different

Electric field strength is a ________________ quantity.

• scalar

• vector

Unit for electric field strength is

• N C^-1

• N m

• kg ms^-2

• kg ms^-1

Tags

NGSS.HS-PS2-4

Electric field strength for a parallel plates is given by equation

• E = F/q

• E= V/d

• E = ½mv²

• E = mgh

Tags

NGSS.HS-PS3-5

The field strength of a positive test charge placed in the field E is

• E = F/q

• E = V/d

• E = ½mv²

• E= mgh

Tags

NGSS.HS-PS3-5