6-2 Practice Kites

Given Kite CDEF,

If DS = 16, find DF.

• DF = 8

• DF = 16

• DF = 32

• DF = 24

Answer explanation

DF is bisected by CE.

Given kite CDEF, find m∠D.

• 45°

• 60°

• 90°

• 120°

Answer explanation

Sum of all angles in a quadrilateral is 360°.

Since CDEF is a kite m∠D = m∠F.

360 - (110 + 70) = 180

180 ÷ 2 = 90

m∠D = 90°

Given Kite PSRQ, find m∠P.

(a)  

Given kite DEFG, find m∠GFD.

• 47°

• 43°

• 94°

• 15.5°

Answer explanation

The kite is made into two congruent triangles by SSS, so corresponding angle are congruent.

Tags

CCSS.HSG.CO.C.9

Given Kiet EFGH, find m∠HZG.

(a)  

Answer explanation

The diagonals of a kite are perpendicular. They form a right angle.

Given kite KLMN, Find m∠LMK.

• 22°

• 11°

• 41°

• 82°

Answer explanation

Segment MK bisects ∠LMN

Find value of x

4x - 3 = 3x + 8

Solve for x and then sub value of x into the expression for ∠LMN

Given TK = 24, SK = 7, find SV.

• SV = 25

• SV = 31

• SV = 24

• SV = 17

Answer explanation

The diagonals of a kite are perpendicular. so, ΔTKS is a right triangle.

Use the Pythagorean theorem with the given sides of the right triangle.

24² + 7² = c² c = SV

625 = c²

c = √(625) = 25

SV = 25

Given TP= 12, WT = 15, find WP.

• 9

• 10

• 11

• 12

Answer explanation

The diagonals of a kite are perpendicular. so, ΔTWP is a right triangle.

Use the Pythagorean theorem with the given sides of the right triangle.

12² + b² = 15² b = WP

b² = 81

b = √(81) = 9

WP = 9

Tags

CCSS.HSG.CO.C.11

Find the area of the kite with diagonals measuring 9 yd and 6 yd.

• 27 square yards

• 54 square yards

• 18 square yards

• 36 square yards

Answer explanation

Use the formula for the area of a triangle.

A = ½BH

There are two triangles with a base of 9 and a height of 3

one triangle area is ½(3)(9) = 13.5

times by two

13.5 *2 = 27

Area of kite is 27 square yards.

Tags

CCSS.6.G.A.1

Given Kite ABCD, find AC.

• 20

• 40

• 21

• 42

• 41

Answer explanation

AC is being bisected by BD, so

AC = 2(EC)

AC = 40