Limited Reaction

Quiz
•
Chemistry
•
10th Grade
•
Hard
Standards-aligned
Charles Martinez
FREE Resource
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
3NH4NO3 + Na3PO4 --> (NH4)3PO4 + 3 NaNO3
Assuming we start with 30 g of NH4NO3 and 50 g of Na3PO4, identify the limiting reactant.
ammonium phosphate
sodium phosphate
ammonium nitrate
sodium nitrate
Tags
NGSS.HS-PS1-7
2.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
3NH4NO3 + Na3PO4 --> (NH4)3PO4 + 3 NaNO3
What is the maximum amount of each product that can be formed?
18.6 g of ammonium phosphate, 31.9 of sodium nitrate
54 g of ammonium phosphate, 31.9 of sodium nitrate
32.4 g of ammonium nitrate, 76 g of sodium phosphate
21 g of ammonium nitrate, 34 g of sodium phosphate
Tags
NGSS.HS-PS1-7
3.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
3NH4NO3 + Na3PO4 --> (NH4)3PO4 + 3 NaNO3
How much of the excess reagent is left over after the reaction is complete?
12 g of sodium phosphate
29.5 g of sodium phosphate
17 g of ammonium nitrate
95 g of ammonium phosphate
Tags
NGSS.HS-PS1-7
4.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
3CaCO3 + 2FePO4 --> Ca3(PO4)2 + Fe2(CO3)3
Assuming we start with 100 g of CaCo3 and 45 g of FePO4, identify the limiting reagent.
iron(V) phosphate
calcium carbonate
iron(III) phosphate
calcium(II) carbonate
Tags
NGSS.HS-PS1-7
5.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
3CaCO3 + 2FePO4 --> Ca3(PO4)2 + Fe2(CO3)3
What is the maximum amount of each product that can be formed?
85 g of calcium carbonate, 39 g of iron(III) phosphate
12.4 g of calcium phosphate, 27 g of iron(III) carbonate
37.2 g of calcium phosphate, 29.3 g of iron(III) carbonate
46.3 g of calcium phosphate, 43.8 g of iron(III) carbonate
Tags
NGSS.HS-PS1-7
6.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
3CaCO3 + 2FePO4 --> Ca3(PO4)2 + Fe2(CO3)3
How much of the excess reagent is left over after the reaction is complete?
57.3 g of sodium phosphate
54.0 g of calcium carbonate
25 g of calcium carbonate
16.9 g of iron(III) carbonate
Tags
NGSS.HS-PS1-7
7.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
CuCl2 + 2NaNO3 --> Cu(NO3)2 + 2NaCl
If 15.0 grams of CuCl2 react with 20 g of NaNO3, how much NaCl can be formed?
13.0 g of NaCl
98 g of NaCl
26 g of NaCl
17.4 of NaCl
Tags
NGSS.HS-PS1-7
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